If
       Ax + By = Cz
where A,B,C,x,y,z
are positive integers and x,y,z > 2, then A, B, C must all share
a common factor greater than 1, i.e. gcd(A,B,C) > 1.
No numerical counter-examples have been found yet. Is it true? By embedding the problem in a larger space will it lead to a simpler proof of Fermat's Last Theorem?
It is easy to show that if Beal's Conjecture is true then it
implies Fermat's Last Theorem: since
for x = y = z > 2 , assume a solution A, B, C and
then divide the equation the common factor= [gcd(A,B,C)]x,
and you get a new solution with gcd(A',B',C') = 1, in
contradiction of Beal's conjecture. Thus
there can be no solutions for x = y = z > 2. This was conjectured by
Fermat in the 1600's and proved recently by Wiles.
Is the rest of Beal's conjecture true? i.e. with x y z not all equal?
More information may be found at Prof. Daniel Mauldin's website.
A Probabilistic Model of the Solutions
to
Ax + By = Cz
Abstract:
An intuitive look into the solutions to
Ax + By = Cz
(where A, B, C, x, y, and z are positive integers)
is done by creating a heuristic model of the "probability" of
solving the equation. The resulting
probability distributions are intended to guide computational
searches for counter-examples to Beal's
conjecture, which is: A, B, C always have a common factor if
x, y, z > 2.
This simple treatment also
actually reproduces some known results about the finiteness of the
number of solutions for small x, y, and z.